For what value of n is the polynomial f(x) = 2x^(3) – nx^(2) + 5x + 9 exactly divisible by x + 2?
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f (x) = 2 x³ - n x² + 5 x + 9
divisor = x + 2
f (-2) = reminder when f(x) is divided by x+2
= 2 (-2)³ - n (-2)² + 5 (-2) + 9
= -16 - 4 n - 10 + 9
= - 4n -17
if reminder is to be 0, then n = - 17/4
divisor = x + 2
f (-2) = reminder when f(x) is divided by x+2
= 2 (-2)³ - n (-2)² + 5 (-2) + 9
= -16 - 4 n - 10 + 9
= - 4n -17
if reminder is to be 0, then n = - 17/4
Answered by
1
Remainder when f(x) is divisible by (x+a) is f(-a).
f(-2) = 2(-2)³ - n(-2)² + 5(-2) + 9
f(-2) = 2(-8) - n(4) - 1
f(-2) = -16 - 4n - 1
f(-2) = -17 - 4n
To divide exactly, the remainder has to be equal to 0
-17 - 4n = 0
-4n = 17
n = -17/4
f(-2) = 2(-2)³ - n(-2)² + 5(-2) + 9
f(-2) = 2(-8) - n(4) - 1
f(-2) = -16 - 4n - 1
f(-2) = -17 - 4n
To divide exactly, the remainder has to be equal to 0
-17 - 4n = 0
-4n = 17
n = -17/4
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