Question

for what value of n term of ap 63,65,67... and 3,10,17... are equal​

Answer 1

Answer:

13

Step-by-step explanation:

A. P.1 - 63,65,67,.......

A. P. 2 - 3,10,17,......

In first A. P. ..

an =63+(n-1) 2

=63+2n-2

an =61+2n

In second A. P.

an =3+(n-1) 7

=3+7n-7

an =7n-4

we know that both ' an ' are equal

so 61+2n = 7n-4

65 = 5n

n = 13

hence solved........