For what value of n terms,the nth terms of an arithmetic progression 63,65,67.......and also find this term
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2
Answer:
Xn=dn+(f-d)
=2n+(63-2)
=2n+61
value of nth terms =2n+61
BY USING THIS ALEGEBRIC TERM WE CAN FIND ANY TERMS
SUPPOSE LETS CALCULATE THE 25th TERM
=2n+61
= 2x25+61
=50+61
=111
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