for what value of N, the......
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tn=? , t1=1,t2=7
therefore
d = t2 - t1 = 7 - 1 = 6
tn = a + (n -1) ×d
tn = 1 + ( n - 1) × 6
tn = 1 + (6n - 6)
tn = 1 +(-6) + 6n
19= 1 - 6 + 6n
19 = -5 + 6n
19 + 5 = 6n
24=6n
n = 24÷6
n = 4
therefore
d = t2 - t1 = 7 - 1 = 6
tn = a + (n -1) ×d
tn = 1 + ( n - 1) × 6
tn = 1 + (6n - 6)
tn = 1 +(-6) + 6n
19= 1 - 6 + 6n
19 = -5 + 6n
19 + 5 = 6n
24=6n
n = 24÷6
n = 4
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