Question

for what value of n the n th terms of the following two APs are equal ? 23,25,27,29 and -17,-10,-1,4​ ​

Answer 1

Answer:

Heya,

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Let the first term of AP be 'a'

i.e a=27

Let the common difference between two consecutive terms of an AP be 'd'

i.e d= 23-27 = -4

Let the last term(nth term) be tn

i.e an=-65

Acoording to the formula,

an= a+(n-1)*d

=> -65=27+(n-1)(-4)

=> -65=27-4n+4

=> 4n=27+4+65

=> 4n=96

=> n=24

n denotes the number of terms in AP

Now let us find 11th term

a11=27+(11-1)(-4)

a11=27-40

a11= -13

The answer is -13

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hope this helped u,

cheers

Step-by-step explanation: