for what value of n, the nth term of arithmetic progression 63,65,67,.......and nth term of arithmetic progression 3,10,17,......are equal to each other?
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Answered by
7
a+(n-1)d = a+(n-1)d
63+(n-1)2 = 3+(n-1)7
63-3+2n-2=7n-7
63-3-2+7=7n-2n
65=5n
n=13
63+(n-1)2 = 3+(n-1)7
63-3+2n-2=7n-7
63-3-2+7=7n-2n
65=5n
n=13
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1
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