Question

for what value of n the nth term of the ap 63,65,76 and 3,100,17 are equal also find that term​

Answer 1

Answer:

First AP

a=63

d=a2-a1 = 65-63 = 2

an=a+(n-1)d

   =63+(n-1)2

   =63+2n-2

   =61+2n

Second AP

a=3

d=a2-a1 = 10-3 = 7

an=a+(n-1)d

   =3+(n-1)7

   =3+7n-7

   =7n-4

According to the question,

nth term of 1st AP = nth term of 2nd AP

61+2n = 7n-4

61+4 = 7n-2n

65 = 5n

n = 65/5

n = 13

Hence, n=13