For what value of n, the nth terms of the arithmetic progressions 63,65,67,... and 3,10,17,...are equal?
Answers
Answered by
5
Answer:
13
Step-by-step explanation:
nth term in both sides are equal.
So: 63+(n-1)2=3+(n-1)7
63+2n-2=3+7n-7
5n=65
n=13
Therefore 13th term of both AP are equal.
Please mark this answer as brainliest.
Similar questions