. For what value of n, the nth terms of the arithmetic progressions
63, 65, 67, --- and 3, 10, 17, ... are equal?
Answers
Answered by
0
Answer:
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Answered by
2
Answer:
87.
Step-by-step explanation:
For the A.P. 63,65,67....
a= 63
d= 65-63=2
a n= a+(n-1)d
=63+(n-1)2
=2n+61
For the A.P.
a=3
d=7
a n =a+(n-1)d
=3+(n-1)7
=7n-4
According to the question,
2n+61=7n-4
65=5n
n=13
Putting n=13 in 2n+61
The term is 2×13+61
=87
13th term of both A.P.s are equal and the term is 87.
hope it helps..
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