For what value of n the sum of first n natural numbers is 66
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let the ist value be x
and second value be x+1
and third value be x+2
a/q,
x+x+1+x+2=66
3x+3 =66
3x=66-3
3x=63
x=63/3
x= 21
then
x=21
x+1=21+1=22
x+2=21+2=23
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and second value be x+1
and third value be x+2
a/q,
x+x+1+x+2=66
3x+3 =66
3x=66-3
3x=63
x=63/3
x= 21
then
x=21
x+1=21+1=22
x+2=21+2=23
PLEASE MARK ME BRANLIEST
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