for what value of n would 1.5×n be greater than n2
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Given : 1.5×n greater than n²
To Find : Value of n
Solution:
1.5×n greater than n²
1.5n > n²
=> 1.5n - n² > 0
=> n ( 1.5 - n) > 0
Either both + ve or both - ve
if n is - ve then 1.5 - n is always + ve
Hence n must be greater than 0
n > 0
case 2 n is + ve
=> 1.5 - n > 0
=> n < 1.5
0 < n < 1.5
0 < n < 1.5 1.5×n be greater than n²
n ∈ (0 , 1.5 )
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