Question

for what value of p,1 is a zero of the polynomial f(x)=2x^2+5x-(3p+1)​

Answer 1

Answer:

p = 8/3

Step-by-step explanation:

=> f(x)=2x^2+5x-(3p+1)

1 is the zero of polynomial f(x). So, x = 1

So,

=> 2x^2+5x-(3p+1) = 0

=> 2(1)^2 + 5(1) - (3p + 1) = 0

=> 2 + 5 -3p + 1 = 0

=> 8 - 3p = 0

=> 3p = 8

=> p = 8/3

Hope, my answer helps you.

Answer 2

SOLUTION

GIVEN

1 is a zero of the polynomial

$\sf f(x) = 2 {x}^{2} + 5x - (3p + 1)$

TO DETERMINE

The value of p

EVALUATION

Here the given polynomial is

$\sf f(x) = 2 {x}^{2} + 5x - (3p + 1)$

Now it is given that 1 is a zero of the polynomial

So we have f(1) = 0

$\displaystyle \sf{ \implies } 2 \times {1}^{2} + (5 \times 1) - (3p + 1) = 0$

$\displaystyle \sf{ \implies } 2 + 5 - (3p + 1) = 0$

$\displaystyle \sf{ \implies } - (3p + 1) = - 7$

$\displaystyle \sf{ \implies } (3p + 1) = 7$

$\displaystyle \sf{ \implies } 3p = 6$

$\displaystyle \sf{ \implies } p = 2$

FINAL ANSWER

Hence the required value of p = 2

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