For what value of p, (–3) is a zero of the polynomial x2 – 5x – (3p + 1)?.
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therefore the value of p ===== 23/3
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substitute X = -3 in the above eqn
(-3)(2)-(5)(-3)-(3p+1)
-6+15-3p-1=0
9-1-3p=0
8-3p=0
-3p=-8
p=8/3
(-3)(2)-(5)(-3)-(3p+1)
-6+15-3p-1=0
9-1-3p=0
8-3p=0
-3p=-8
p=8/3
killerknight692:
actually x2 means x raise to power 2
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