For what value of p, -4 is a zero of the polynomial x^2-2x-(2p+3)
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since -4 is a zero of given polynomial
thus it satisfies eqn
![{x}^{2} - 2x - (2p + 3) = 0 \\ { - 4}^{2} - 2( - 4) - (2p + 3)] = 0 \\ 16 + 8 - 2p - 3 = 0 \\ 21 - 2p = 0 \\ p = \frac{21}{2}](https://tex.z-dn.net/?f=+%7Bx%7D%5E%7B2%7D+-+2x+-+%282p+%2B+3%29+%3D+0+%5C%5C+%7B+-+4%7D%5E%7B2%7D+-+2%28+-+4%29+-+%282p+%2B+3%29%5D+%3D+0+%5C%5C+16+%2B+8+-+2p+-+3+%3D+0+%5C%5C+21+-+2p+%3D+0+%5C%5C+p+%3D+%5Cfrac%7B21%7D%7B2%7D+ "{x}^{2} - 2x - (2p + 3) = 0 \\ { - 4}^{2} - 2( - 4) - (2p + 3)] = 0 \\ 16 + 8 - 2p - 3 = 0 \\ 21 - 2p = 0 \\ p = \frac{21}{2}")
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thus it satisfies eqn
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