Question

For what value of P, (-4) is a zero of the
polynomial
x²-2x-(7p+3).​

Answer 1

Answer:

answer is 3

Step-by-step explanation:

you have to put the value ‐4 in equation x^2‐2x‐(7p+3)

so after that we get 16+8‐7p‐3=0

7p=21

therefore p=3

Answer 2

Answer

$\sf{If -4 \: is \: zero \: of \: given \: polynomial \: then} \\ \\(−4)2−2(−4)−(7p+3)=0 \\ \\ ⇒16+8−7p−3=0 \\ \\ ⇒7p=21 \\ \\ ⇒p=3$