For what value of p, -4 is a zeroes of the polynomial x 2 -2x-(7p+3) ?
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If α,β are the zeros of x²-2x-(7p+3)=0 where α=-4
then, α+β=-(-2/1)
or, -4+β=2
or, β=2+4
or, β=6
then, α×β=-(7p+3)/1
or, -(7p+3)=-4×6
or, -7p-3=-24
or, -7p=-24+3
or, -7p=-21
or, p=21/7=3
then, α+β=-(-2/1)
or, -4+β=2
or, β=2+4
or, β=6
then, α×β=-(7p+3)/1
or, -(7p+3)=-4×6
or, -7p-3=-24
or, -7p=-24+3
or, -7p=-21
or, p=21/7=3
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