for what value of p,(-4) is the zero of the polynomial x square minus 2x minus 2p plus 3
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Hey mate! Thanks for asking your question,
Given, -4 is a zero of p(x)
Where p(x) = [tex] x^2 - 2x - 2p + 3[\tex]
Thus according to the question;
=> p(-4) = 0
=> [tex] 2(-4)^2 - 2(-4) - 2p + 3 = 0[/text]
=> 2(16) + 8 - 2p + 3 = 0
=> 32 + 11 - 2p = 0
=> 2p = 43
=> p = 43/2
I hope it helps you! #thanks
Given, -4 is a zero of p(x)
Where p(x) = [tex] x^2 - 2x - 2p + 3[\tex]
Thus according to the question;
=> p(-4) = 0
=> [tex] 2(-4)^2 - 2(-4) - 2p + 3 = 0[/text]
=> 2(16) + 8 - 2p + 3 = 0
=> 32 + 11 - 2p = 0
=> 2p = 43
=> p = 43/2
I hope it helps you! #thanks
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