Question

For what value of p, (-4) of a zero of the polynomial x²-2x-(7p+3)

Answer 1

Answer:

so p will be 3

Explanation:

put x = -4

(-4)^2-2(-4)-(7p+3)=0

16+8-(7p-3)=0

24-7p-3 =0

21-7p = 0

7p =21

p = 21/7

p = 3

Answer 2

Answer

$\sf{If -4 \: is \: zero \: of \: given \: polynomial \: then} \\ \\(−4)2−2(−4)−(7p+3)=0 \\ \\ ⇒16+8−7p−3=0 \\ \\ ⇒7p=21 \\ \\ ⇒p=3$