Question

For what value of p, (-4) of a zero of the polynomial x²-2x-(7p+3)​

Answer 1

Answer:

p = 3

Step-by-step explanation:

x²-2x-(7p+3)​

put x = -4

(-4)² - 2*(-4) - (7p+3) = 0

16 + 8 - 7p - 3 = 0

7p = 24 - 3 = 21

p = 21/7 = 3

Answer 2

Answer:

P=3

Step-by-step explanation:

-4. = zero of polynomial

So putting -4. In place of x

(-4)^2 -2(-4) -(7p+3)=0

16+8 -(7p+3)=0

24-(7p+3)=0

7p+3=24

7p=24-3

7p=21

P=21÷7

P=3