Question

for what value of p,-4is a zero of polynomial x2-2x-(7p+3)?​

Answer 1

Answer:

X²-2x-(7p+3)=0

(-4)²-2(-4)-7p-3=0

16+8-3-7p=0

21-7p=0

-7p=-21

p=21/7

p=3

If p = 3 , then (-4) is a factor of p(x)

Step-by-step explanation:

polynomial.

Now, we need to find the value of p.

Let, f(x)=  

Given that x+4 is a factor, applying f(-4) in the above equation, we get f(-4) = 0

Substitute x=-4 in the given equation,  

Now we get,f(-4) = (-4)2-2(-4)-(7p+3)

On substituting the above equation, we get,16 + 8 –(7p + 3) = 0

Now, simplifying the above equation,

24 = 7p+3

7p = 21

p=3

Hence, the value of p is found to be 3, ∴p = 3

Answer 2

the equation is,

x2-2x-(7p+3)

x2-2x-7p-3

p(x)=(-4)^2-2*-4-7p-3

= 16+8-7p-3=> 21=7p

= p= 3