Question

for what value of p,4x + py + 8= 0 and 2x + 2y + 2=0 will have unique solution​

Answer 1

Answer:

Take the value of p=8

Step-by-step explanation:

For unique solution we need a1/a2 $\neq$ b1/b2

4x+py+8=0

2x+2y+2=0

a1=4  b1=p  c1=8

a2=2 b2=2  c2=2

a1/a2=4/2

        =2

We will need a no. which doesn't make b1/b2=2

We will take the value of p=8