Question

For what value of p are 2p+1,13,5p-3 three consecutive terms of an AP​

Answer 1

Step-by-step explanation:

To be in AP, d1=d2

a2-a1=a3-a2

13-(2p+1)=(5p-3)-13

13-2p-1=5p-3+13

-2p+12=5p+10

-7p=-2

p=2/7

hope it helps!!!