Question

for what value of p are 2p+1 ,13,5p-3 three consecutive terms of an AP

Answer 1

Hello Frnd

Here is your answer.

Given terms of AP as

2p + 1, 13 and 5p - 3

Since it's an AP

There fore it's difference must be common

to calculate that

$> > \: a_{2} - a_{1} \: = a_{3} - a_{2}$
And here
$a_{1} = 2p + 1 \\ a_{2} = 13 \\ a_{3} = 5p - 3 \\ \\ putting \: the \: values \: in \: formula$
>>> 13 - ( 2p + 1) = 5p - 3 - 13
>>> 13 - 2p - 1 = 5p - 16
>>> 12 - 2p = 5p - 16
>>> 12 + 16 = 5p + 2p
>>> 28 = 7p
>>> p = 4

hence the value of p will be 4


hope it helps
#jerri