for what value of P are 2P+1, 13, 5P-3 three consecutive terms of AP
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Answered by
15
2P +1 -13=13-5p+3
2p -12=16-5p
7p =28
P =4
2p -12=16-5p
7p =28
P =4
bhaskar314:
thanks
Answered by
6
i think that.......................
2p+1-13=13-5p+3
2p-12=16-5p
7p=28p=4
please mark it as a ntainlist
2p+1-13=13-5p+3
2p-12=16-5p
7p=28p=4
please mark it as a ntainlist
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