Question

For what value of p,are 2p+1,13 and 5p-3 Three consecutive terms of Ap

Answer 1

$\huge\underline\mathfrak\pink{Answer}$

Solution:

Given 2p+1, 13 , 5p-3 are in AP.

To find: value of P

If a,b,c are in AP then we know that

2b=( a+c)

Here a= 2p+1

b=13

c=5p-3

2 (13) =(2p+1+5p-3)

26=7p-2

26+2=7p

28=7p

p=28/7 =4

Therefore the value of

P is 4.

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Answer 2

$\huge{\underline{\underline{\mathfrak{Answer}}}}$

SOLUTION:

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⭐️Given 2p+1, 13 , 5p-3 are in AP.

⭐️To find: value of P

⭐️If a,b,c are in AP then we know that

⭐️2b=( a+c)

⭐️Here a= 2p+1

⭐️b=13

⭐️c=5p-3

⭐️2 (13) =(2p+1+5p-3)

⭐️26=7p-2

⭐️26+2=7p

⭐️28=7p

⭐️p=28/7 =4

⭐️Therefore the value of

⭐️P is 4.

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$\huge{\underline{\underline{\mathfrak{Thank you}}}}$