Question

For what value of P, are 2p-1, 7 and 3p three consecutive terms of an A.P.

Answer 1

Given :-

2p - 1 , 7 , 3p

are in A.P

As we know they the half of the sum of the a.p. is equal to the middle one

$\frac{2p - 1 + 3p}{2} = 7$

$5p - 1 = 14$

5p = 14 + 1

5p = 15

p = 3

Answer 2

p = 3
use a2-a1 = a3-a2