For what value of p are 2p-1,7 and 3p three consecutive terms of an AP?
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Answered by
3
3p-7=7-(2p-1)
3p-7=7-2p+1
3p+2p=1
5p=1
p=1/5
3p-7=7-2p+1
3p+2p=1
5p=1
p=1/5
Prashantbharti2:
Thanx
Answered by
0
14= 2p-1+3p
p=3....... .
p=3....... .
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