For what value of p, are 2p-1, 7 and 3p three consecutive terms of an A.P?
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Answer:
3
Step-by-step explanation:
given:−
2p−1,7,3p are in A.P
As we know the half of the sum of the A.P is equal to the middle one
2
2p−1+3p
=7
5p−1=14
5p=14+1
5p=15
p=3.
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