for what value of 'p' does the pair of equations given below has unique solution 4x+py+8=0 and 2x+2y+2=0
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4x +py+8=0 _(i)
2x+2y+2=o_(ii)
take eq(ii) 2x+2y+2=0
⇒2x=-2y-2
⇒x=-2y-2÷2
⇒x=-y-1
now 2(-y-1)+2y+2=0
⇒-2y-2+2y+2=o
p=0
2x+2y+2=o_(ii)
take eq(ii) 2x+2y+2=0
⇒2x=-2y-2
⇒x=-2y-2÷2
⇒x=-y-1
now 2(-y-1)+2y+2=0
⇒-2y-2+2y+2=o
p=0
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