Question

For what value of ‘p’ if ( i+j+k)p a unit vector?​

Answer 1

pi+pj+pk is the given vector.

For the vector to be unit, it's magnitude must be 1.

=>

$\sqrt{ {p}^{2} + {p}^{2} + {p}^{2} } \: = 1 \\ \sqrt{3 {p}^{2} } = 1 \\ p = + \frac{1}{3} or \: - \frac{1}{3}$

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