. For what value of ‘p’ is the function f(x) = {
1−cos 4
2
, ≠ 0
, = 0
is
continuous at x = 0
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0
Answer:
= lim f(x) = f(0)
x-›0
lim 4×2sin^2x/4x^2 = p
x-›0
p=8
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