Question

for what value of p, line px-2y+1=0 is perpendicular to the line joining the point (1,3) and (p,2)?​

Answer 1

Step-by-step explanation:

2y=px+1

slope m1=p/2

slope m2=2-3/p-1=-1/p-1

m1*m2=-1

-p/2(p-1)=-1

p=2p-2

p=2