Math, asked by Abhiramalayil998, 1 year ago

For what value of p, p + 2, 4p – 6 and 3p – 2 are three consecutive terms of an AP?

Answers

Answered by Anonymous
13

4p-6-p-2 = 3p-2-4p+6

solving we get p =3 and the numbers are 5, 6, 7.

Answered by 595BVS
19
hope it is helpful for you it
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