Question

For what value of p the equation
(1 + p)x2 +2(1+2p)x +(1+p) = 0
​

Answer 1

Step-by-step explanation:

If b^2 - 4ac = 0, then there are 2 equal roots.

[2(1 + 2p)]^2 - 4(1 + p)(1 + p) = 0

4(1 + 4p + 4p^2) - 4(1 + 2p + p^2) = 0

4 + 16p + 16p^2 - 4 - 8p - 4p^2 = 0

12p^2 + 8p = 0

4p(3p + 2) = 0

4p = 0 or 3p + 2 = 0

p = 0 3p = -2

p = -2/

Answer 2

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