Math, asked by vaishnavi1929, 4 months ago

for what value of p the equation 2x^2+3px+1=0 has equal roots?​

Answers

Answered by mathdude500
8

Answer:

Since equation have equal roots

so discriminant = 0

 {b}^{2}  - 4ac = 0 \\  {(3p)}^{2}  - 4(2)(1) = 0 \\ 9 {p}^{2}  - 8 = 0 \\ 9 {p}^{2}  = 8 \\  {p}^{2}  =  \frac{9}{8}  \\ p =  \frac{3}{2 \sqrt{2} }  \: or \:  -  \frac{3}{2 \sqrt{2} }

Answered by gp875686
3

Step-by-step explanation:

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