Question

for what value of p, the equation (p+3)x²-(5-p)x+1=0has coincident roots
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Answer 1

Answer:

p=1,3

Step-by-step explanation:

(p+3)x²-(5-p)x+1=0

a=(p+3)

b=-(5-p)

c=1

find the value of p

it has same roots discriminant=0

Δ=b²-4ac

(-(5-p))²-4(p+3)=0

(5-p)²-4(p+3)=0

5²+p²-10p-4p-12=0

25+p²-14p-12=0

p²-14p+13=0

p²-p-13p+13=0

p(p-1)-13(p-1)=0

(p-1)(p-13)=0

p=1,3