Question

for what value of p, the equation px²-18x+1 =0 is a perfect square​

Answer 1

Step-by-step explanation:

 

D=b^2-4×a×c

=324-4p=0

4p=324

p=81

since perfect square I think p is 9

3.8

Answer 2

p = 81

Given:-

• px²- 18x + 1 = 0

To find:-

• Value of p

Solution:-

★ Any quadratic equation is perfect square when its root are equal.

⟹ b² - 4ac = 0 [∵ real roots]

⟼ (- 18)² - 4 × p × 1 = 0

⟼ 324 - 4p = 0

⟼ - 4p = -324

⟼ p = -324/4

⟼ p = 81

∴ Therefore, when p = 81 then the given equation px² - 18x + 1 = 0

is a perfect square.

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