Question

FOR WHAT VALUE OF p THE FOLLOWING PAIR OF EQUATIONS HAS UNIQUE SOLUTION. 2x+py=-5 AND 3x+3y=-6​

Answer 1

Answer:

hello here is your answer friend...

Step-by-step explanation:

quadratic equations

2x + py = - 5 and 3x + 3y = - 6

have unique solution

Then,

a1/a2 = b1/b2

a1 = 2, b1 = p, a2 = 3, b2 = 3

2/3 = p/3

6 = 3p

p = 6/3 = 2

Value of p = 2

hope it works...

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Answer 2

Step-by-step explanation:

2x + py = - 5

3x + 3y = - 6

2x + py + 5 =0

3x + 3y + 6 =0

a¹ ≠ b¹

a² b²

2 ≠ p

3 3

3 × p ≠ 2×3

3p ≠ 6

p ≠ 6/3

P ≠ 2