For what value of p , the following terms are three consecutive terms of an A.p. 4/5 , p , 2
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Given: ⅘, p, 2 will be consecutive terms of an AP
Here, first term = ⅘
Second term= p
third term = 2
Second term - first term = third term - second term
(p) - ⅘ = 2 - p
p + p = 2 + ⅘
2p = (2× 5 +4) /5
2p = (10+4)/5
2p = 14 / 5
p = 14/(5×2)
p = 7/5
Hence, the value of p is 7/5.
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