Question

For what value of p the given equation px^2 -2x +2 =0 has real roots​

Answer 1

Answer: p=1/2

here, a=p, b=-2, c=2

if equation has 2 real roots then, Discriminant is greater than or equal to zero.

Discriminant (D)=   b² - 4ac = 0

                      (-2)  ² - 4(p)(2) = 0

                            4 - 8p = 0

                                 8p = 4

                                  p = 1/2

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Answer 2

Given; px^2 -2x +2 =0

To Find; For what value of p does the given equation px^2 -2x +2 =0 have real roots​

Solution; An equation has equal roots if D is greater than or equal to zero

a=p, b=-2 , c=2

D= $b^{2} -4ac$=4-8p

p=2

Hence p should be  greater than equal to 2