For what value of p the number 3p+2,4p+3 and 6p-1 are Ap
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Step-by-step explanation:
To be in AP 4p + 3 - (3p + 2 ) = 6p - 1 - (4p + 3) => 4p + 3 - 3p -2 = 6p - 1 - 4p - 3
=> p + 1 = 2p - 4 => p = 5
shriyancs:
p+1=2p-4 -》1+4=2p-p -》5=p OR p=5
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