For what value of p the pair of equations 2x+py=-5 and 3x+3y=-6 has a unique solution
Godadevi:
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Answered by
24
P should not be equal to 3
If p=3 then the lines become parallel then there will be no solution
To have unique solution p should not be equal to 3
If p=3 then the lines become parallel then there will be no solution
To have unique solution p should not be equal to 3
Answered by
92
HI !
2x + py = -5 => 2x + py + 5 = 0
a₁ = 2 , b₁= p , c₁ = 5
================================
3x + 3y = -6 => 3x + 3y + 6 = 0
a₂ = 3 , b₂ = 3 , c₂ = 6
As they have unique solution ,
a₁/a² ≠ b₁/b₂
2/3 ≠ p/3
3p ≠ 6
p ≠ 3
the pair of equations will have unique solution , for all values of p except 3
2x + py = -5 => 2x + py + 5 = 0
a₁ = 2 , b₁= p , c₁ = 5
================================
3x + 3y = -6 => 3x + 3y + 6 = 0
a₂ = 3 , b₂ = 3 , c₂ = 6
As they have unique solution ,
a₁/a² ≠ b₁/b₂
2/3 ≠ p/3
3p ≠ 6
p ≠ 3
the pair of equations will have unique solution , for all values of p except 3
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