Question

For what value of p the pair of linear equation 2x+3y =7 and 4x+6y+p=0 are coincident​

Answer 1

Answer:

p= -14

Step-by-step explanation:

2x+3y-7=0, a₁= 2, b₁= 3, c₁= -7

4x+6y+p=0, a₂= 4, b₂= 6, c₂= p

If equations are coincident,

a₁/a₂ = b₁/b₂ = c₁/c₂

2/4= 3/6 = -7/p

1/2 = -7/p

p= -14

Therefore the value of p should be -14.

Please mark me as brainliest if this helped.

Answer 2

Answer:

The value of p = -14

Step-by-step explanation:

Given,

The pair of equation 2x+3y =7 and 4x+6y+p=0 are coincident

To find,

The value of p

Solution:

Recall the concept:

The pair of linear equations a₁x + b₁y + c₁ = o and a₂x+b₂y+c₂ = 0 are coincident if

$\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$ -------------(1)

Comparing the given equations 2x+3y =7 and 4x+6y+p=0 with a₁x + b₁y + c₁ = o and a₂x+b₂y+c₂ = 0 we get,

a₁ = 2, b₁ = 3 and c₁ = -7

a₂ = 4, b₂ = 6 and c₂ = p

Since the given equations are coincident, by the condition (1) we have

$\frac{2}{4} = \frac{3}{6} = \frac{-7}{p}$

$\frac{1}{2} = \frac{-7}{P}$

p = -14

The value of p = -14

#SPJ3