Question

For what value of p the point (p,0) lies on the line 3x + y = 11 ?

Answer 1

Answer:

$x = p \\ y = 0 \\ 3x + y = 11 \\ put \: the \: value \: of \: x \: and \: y \\ 3p + 0 = 11 \\ 3p = 11 \\ p = \frac{11}{3}$

Answer 2

Question :–

▪︎ For what value of p the point (p,0) lies on the line 3x + y = 11 ?

Answer :–

$\\ \longrightarrow \large { \red{ \boxed{\bold{ \: p= \frac{11}{3} }}}}$

EXPLANATION :–

GIVEN :–

▪︎ A point (p,0) lies on the line 3x + y = 11 .

TO FIND :–

▪︎ Value of p = ?

SOLUTION :–

▪︎ If a point lies on the line , then the will satisfy the equation.

• Hence , (p,0) will satisfy the equation 3x + y = 11.

$\\ { \bold{ \implies \: 3(p) + 0 = 11}}$

$\\ { \bold{ \implies \: 3p= 11}}$

$\\ \implies \large { \boxed{\bold{ \: p= \frac{11}{3} }}}$

Hence , Value of ${ \bold{ \: p \: \: is \: \: \frac{11}{3} \: . }}$

VERIFICATION :–

• We have to satisfy that a Point ${ \bold { (\dfrac{11}{3} , 0)}}$ will satisfy the given equation .

$\\ { \bold{ \implies \: \cancel3( \frac{11}{ \cancel3} ) + 0 = 11}}$

$\\ { \bold{ \implies \: 11 = 11 \: \: \: \: \: \: \: \: (Verified)}}$