Math, asked by rayabinash07p2yrfu, 1 year ago

for what value of p , the polynomial 2x^3-7x^2-x+p is exactly divisible by (2x+3)

Answers

Answered by RahulCR7

2x+3=0
x=-3/2 (1)
2x^3-7x^2-x+p=0
using value from (1)
2 (-3/2)^3-7 (-3/2)-(-3/2)+p=0
(-3)^3+21/2+3/2+p=0
-27+(21+3/2)+p=0
-27+24/2+p=0
-27+12+p=0
p=15
if satisfied then mark it as brainliest
it's a request!!

rayabinash07p2yrfu: thanks but your answer is wrong as i had the answer but not the question and the actual answer is 21 because if you divide the polynomial by 2x+3 then you get p-21 as the remainder which as per question is equal to 0 which then gives p as 21

Answered by mightyraj2213

This is your answer. I hope you are satisfied with it. Thank you.

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