Question

for what value of p the quadratic equation 16x^2+px+1​

Answer 1

Step-by-step explanation:

Given For what value of p the quadratic equation 16 x^2+p x+1  has equal roots.

• The roots of quadratic equation ax^2 + bx + c = 0 are equal when discriminant is 0, that is b^2 – 4ac = 0
• Here a = 16, b = p, c = 1
• So b^2 – 4ac = 0
• So p^2 – 4(16)(1) = 0
• So p^2 – 64 = 0
• So p^2 = 64

So p = 8

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