Math, asked by samahir1434, 8 months ago

For what value of p ,the quadratic equation (3p -1)x^2+5x+(2p-3)=0

Answers

Answered by syedmohammed7337
1

Step-by-step explanation:

Simplifying

2p + 6 = 4p + -10

Reorder the terms:

6 + 2p = 4p + -10

Reorder the terms:

6 + 2p = -10 + 4p

Solving

6 + 2p = -10 + 4p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-4p' to each side of the equation.

6 + 2p + -4p = -10 + 4p + -4p

Combine like terms: 2p + -4p = -2p

6 + -2p = -10 + 4p + -4p

Combine like terms: 4p + -4p = 0

6 + -2p = -10 + 0

6 + -2p = -10

Add '-6' to each side of the equation.

6 + -6 + -2p = -10 + -6

Combine like terms: 6 + -6 = 0

0 + -2p = -10 + -6

-2p = -10 + -6

Combine like terms: -10 + -6 = -16

-2p = -16

Divide each side by '-2'.

p = 8

Simplifying

p = 8

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