Question

For what value of p the quadratic equation 3x²-5x+p=0 have equal roots

Answer 1

here, a=3 , b= -5 , c= p

D = b^2 -4ac

D = (-5)^2 - 4(3).p

D = 25 - 12p

12p = 25

p = 25/12

therefore , the value of p is 25/12

Answer 2

Answer:

The value of 'p' when the quadratic equation 3x²-5x+p=0 has equal roots =  $\frac{25}{12}$

Step-by-step explanation:

Given,

The quadratic equation 3x²-5x+p=0 has equal roots

To find,

The value of 'p'

Recall the concept

The quadratic equation ax²+bx+c=0, have equal roots if the discriminant

b² - 4ac = 0

Solution:

Given equation is 3x²-5x+p=0

comparing the given equation with ax²+bx+c=0 we get

a = 3, b = -5 and c = p

Since the equation 3x²-5x+p=0, has equal roots we have

b² - 4ac = 0

Substituting the value of a = 3, b = -5 and c = p

(-5)² - 4×3×p = 0

25 - 12p = 0

12p = 25

p = $\frac{25}{12}$

∴The value of 'p' when the quadratic equation 3x²-5x+p=0 has equal roots =  $\frac{25}{12}$

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