Question

For what value of p the quadratic equation
(p + 5)x^2 – (2p+3)x + (p-1) = 0 has no real
root​

Answer 1

Answer:

As the equation has no real roots,

√b^2-4ac < 0

=>√(-2p-3)^2-4(p+5)(p-1) < 0

=>4p^2+9+12p-4(p^2-p+5p-5) < 0

=>4p^2+9+12p-4p^2-16p+20 < 0

=>29-4p < 0

=>p < 29/4