Question

for what value of P , the quadratic equation Px२ + 8x - 2= 0 has real roots.
plse solve it , i want it urgent

Answer 1

hey... MATE !!
here's ur solution,

We have,
a = P
b = 8
c = -2

now,
D = b² -4ac
(8)² - 4 (P) (-2)
= 64 + 8P

for real roots,
D is greater or equal to 0
now,
(used this attachment)

hope it might be helpful !!

Answer 2

Px^2+8x-2
For an equation to have real roots
B
b^2-4ac=0
By condition
8^2-4×p×-2=0
64-8p=0
-8p=-64
P=8
Hope it helps ..if so mark it the brainliest